Hi, when I set log.options.logHandler = myConsole and the call log.info("test") myConsole is not being invoked.
However the following 2 alternatives work fine:
log.console = myConsole and log = new LambdaLog({logHandler: myConsole})
I think this is because internally LambdaLog use the property console and that property is only set during the constructor.
I mention this because the documentation uses log.options.logHandler = myConsole
I'm using version 3.0.0
BTW the property options.logHandler it is not defined in the typescript types.
Thanks
Hi, when I set
log.options.logHandler = myConsoleand the calllog.info("test")myConsoleis not being invoked.However the following 2 alternatives work fine:
log.console = myConsoleandlog = new LambdaLog({logHandler: myConsole})I think this is because internally
LambdaLoguse the propertyconsoleand that property is only set during the constructor.I mention this because the documentation uses
log.options.logHandler = myConsoleI'm using version 3.0.0
BTW the property
options.logHandlerit is not defined in the typescript types.Thanks