Skip to content

Latest commit

 

History

History
63 lines (49 loc) · 1.88 KB

File metadata and controls

63 lines (49 loc) · 1.88 KB

Given an array of integers arr, replace each element with its rank.

The rank represents how large the element is. The rank has the following rules:

  • Rank is an integer starting from 1.
  • The larger the element, the larger the rank. If two elements are equal, their rank must be the same.
  • Rank should be as small as possible.

 

Example 1:

Input: arr = [40,10,20,30]
Output: [4,1,2,3]
Explanation: 40 is the largest element. 10 is the smallest. 20 is the second smallest. 30 is the third smallest.

Example 2:

Input: arr = [100,100,100]
Output: [1,1,1]
Explanation: Same elements share the same rank.

Example 3:

Input: arr = [37,12,28,9,100,56,80,5,12]
Output: [5,3,4,2,8,6,7,1,3]

 

Constraints:

  • 0 <= arr.length <= 105
  • -109 <= arr[i] <= 109

Related Topics:
Array

Solution 1.

// OJ: https://leetcode.com/problems/rank-transform-of-an-array/
// Author: github.com/lzl124631x
// Time: O(NlogN)
// Space: O(N)
class Solution {
public:
    vector<int> arrayRankTransform(vector<int>& arr) {
        set<int> s(arr.begin(), arr.end());
        unordered_map<int, int> m;
        vector<int> ans(arr.size(), 0);
        int i = 0;
        for (auto it = s.begin(); it != s.end(); ++it) m[*it] = ++i;
        for (int j = 0; j < arr.size(); ++j) ans[j] = m[arr[j]];
        return ans;
    }
};